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.54-6x^2=0
We add all the numbers together, and all the variables
-6x^2+0.54=0
a = -6; b = 0; c = +0.54;
Δ = b2-4ac
Δ = 02-4·(-6)·0.54
Δ = 12.96
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-\sqrt{12.96}}{2*-6}=\frac{0-\sqrt{12.96}}{-12} =-\frac{\sqrt{}}{-12} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+\sqrt{12.96}}{2*-6}=\frac{0+\sqrt{12.96}}{-12} =\frac{\sqrt{}}{-12} $
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